Given the sets A = [2, 4, 6, 8] and B = [2, 3, 5, 9]. If a number is selected at random from set B, what is the probability that the number is prime?
1
\(\frac{3}{4}\)
\(\frac{1}{2}\)
\(\frac{1}{4}\)
Correct answer is B
A = [2, 4, 6, 8}
B = {2, 3, 5, 9}
Pr = (Prime in B) = \(\frac{3}{4}\)