The terminal voltage of a battery is 4.0V when supplying a current of 2.0A, and 2.0V when supplying a current of 3.0A. The internal resistance of the battery is
0.5 \(\Omega\)
1.0\(\Omega\)
2.0\(\Omega\)
4.0\(\Omega\)
Correct answer is C
E = 4 + 2r and E = 2 + 3r
therefore, r = 2\(\Omega\)