The energy stored in a spring of stiffness constant k = 2...
The energy stored in a spring of stiffness constant k = 2000Nm−1 when extended 4cm is
0.16J
1.60J
16.00J
160.00J
Correct answer is B
The spring constant = the measure of stiffness = 2000Nm−1
Energy stored in a spring = Work done to stretch it through a distance = change in potential energy
= kx22 = 2000×(0.04)22 (converting 4cm to metres)
= 3.22=1.60J