Two objects P and Q of masses 100kg and 20kg respectively are 1.2m apart on a horizontal surface. Calculate the net gravitational force acting on Q. $[G= 6.67 \times 10^{-11} Nm^{2}kg^{-2}]$

$1.11\times 10^{-7} N$ towards P

$1.11\times 10^{-7} N$ towards Q

$9.26\times 10^{-8} N$ towards P

$9.26\times 10^{-8} N$ towards Q

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Correct answer is D

$F= \frac{Gm_{1}m_{2}}{r^{2}}$

$m_{1} = 100kg$

$m_{2} = 20kg; r =1.2m$

$G= 6.67\times 10^{-11}$

$F = \frac{6.67\times 10^{-11}\times 100\times 20}{(1.2)^{2}} = 9.26\times 10^{-8}$

The acceleration of each object is inversely proportional to the mass, the lighter object will move a bit faster, hence. the force will act in the direction of Q.

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Two objects P and Q of masses 100kg and 20kg respectively are 1.2m apart on a horizontal surface. Calculate the net gravitational force acting on Q. $[G= 6.67 \times 10^{-11} Nm^{2}kg^{-2}]$

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Two objects P and Q of masses 100kg and 20kg respectively are 1.2m apart on a horizontal surface. Calculate the net gravitational force acting on Q. [G=6.67×10−11Nm2kg−2][G= 6.67 \times 10^{-11} Nm^{2}kg^{-2}]

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Two objects P and Q of masses 100kg and 20kg respectively are 1.2m apart on a horizontal surface. Calculate the net gravitational force acting on Q. $[G= 6.67 \times 10^{-11} Nm^{2}kg^{-2}]$