Calculate the time taken for a mango fruit that fall from the tree 20 m to the ground [g = 10 ms^-2]

10s

Correct answer is D

u = , H = 20, g = 10

From equation of motion under gravity

H = ut ± \(\frac{1}{2}\)gt², It is falling so g is +ve

H = 0 + \(\frac{1}{2}\)gt²

H = \(\frac{1}{2}\)gt²

2H = gt²

\(\frac{2H}{g}\) = t²

t = \(\frac{\sqrt{2H}}{g}\)

= \(\frac{\sqrt {2 \times 20}}{10}\)

= √4

= 2s

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