Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative.... Question 10950

Two parallel plates at a distance of 8.0 x 10^-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?

4.8 Vm^-1

75.0Vm^-1

4800.0Vm^-1

75000.0Vm^-1

Correct answer is D

E = \(\frac{voltage}{distance}\)

= \(\frac{600}{8 \times 10^2}\)

= 75000.0Vm^-1

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Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?

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Two parallel plates at a distance of 8.0 x 10^-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?