In the diagram PQR is a straight line and PS is a tangent to the circle < QRS with |PS| = |SR| and < SPR = 40°. Find PSQ
A.
20o
B.
40o
C.
10o
D.
30o
Correct answer is B
PS = SR
\(\bigtriangleup\)PSR is an isosceles
< P = < SPQ = 40°
< R = < SRQ
< PSQ = < SRQ (alternate segment)
< PSQ = 40°