If the diagram is the graph of y = x2, the shaded area is
64 square units
\(\frac{126}{4}\) square units
32 square units
\(\frac{64}{3}\) square units
Correct answer is D
A = \(\int^{x = 4}_{x = 0}\) ydx = \(\int^{4}_{0}\) x2dx = [\(\frac{x^3}{3} + c]^{4}_{0}\)
= \(\frac{64}{3}\) square units
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