TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. find < YTR
A.
108o
B.
121o
C.
140o
D.
148o
Correct answer is A
< TWR = < QTR = 40o (alternate segment)
< TWR = < TXR = 40o(Angles in the same segments)
< YXR = 40o + 32o = 72o
< YXR + < YTR = 180o(Supplementary)
72o + < YTR = 180o
< YTR = 180o - 72o
= 108o