In the diagram, QP//ST:PQR = 34o qrs = 73o and Rs = RT. Find SRT
A.
68o
B.
102o
C.
107o
D.
141o
Correct answer is B
Construction joins R to P such that SRP = straight line
R = 180o - 107o
< p = 180o - (107o - 34o)
108 - 141o = 39o
Angle < S = 39o (corr. Ang.) But in \(\bigtriangleup\)SRT
< S = < T = 39o
SRT = 180 - (39o + 39o)
= 180o - 78o
= 102o