In the diagram, O is the centre of the circle and POQ a diameter. If POR = 96o, find the value of ORQ.
A.
84o
B.
48o
C.
45o
D.
42o
Correct answer is B
OQ = OR = radii
< ROQ = 180 - 86 = 84o
\(\bigtriangleup\)OQR = Isosceles
R = Q
R + Q + 84 = 180(angle in a \(\bigtriangleup\))
2R = 96 since R = Q
R = 48o
ORQ = 48o