In the diagram, PQRS is a circle with O as centre and PQ/RT. If RTS = 32°. Find PSQ
A.
32o
B.
45o
C.
58o
D.
90o
Correct answer is C
< PSO = \(\frac{1}{2}\) < SOQ = \(\frac{1}{2}\)(180) = 90°
< RTS = < PQS = 32° (Alternative angle)
< PSQ = 90 - < PSQ = 90° - 32°
= 58°