In the figure, FGHJ is a circle of radius 3cm centre O. FOH, GOJ are perpendicular diameters. With G as centre of an arc of a circle is drawn to pass through F and H. Find the length of the perimeter of the lunar portion shaded.
3\(\pi\)\(\sqrt{2 - 1}\)cm
\(\frac{9}{2}\)\(\pi\)cm
3 \(\pi\)(1 + \(\frac{2}{2}\))
3(1 + \(\frac{2}{2}\))
Correct answer is C
Perimeter of lunar portion = 3\(\pi\) + \(\frac{3\pi \sqrt{2}}{2}\)
= 3 \(\pi\)(1 + \(\frac{2}{2}\))