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\(\begin{array}{c|c} \text{Class Interval} & Frequency & \te...

Class IntervalFrequencyClass boundariesClassMidpoint1.51.921.451.951.72.02.4211.952.452.22.52.942.452.952.73.02.9152.953.453.23.53.9103.453.953.74.04.453.954.454.24.54.934.454.954.7
Find the mode of the distribution above to find the mode of the distribution.

A.

3.2

B.

3.3

C.

3.7

D.

4.2

Correct answer is B

Mode = a + (b - a)(fm - Fb)

2Fm - Fa - Fb

= 3.0 + (3.43)(154)2(15)410

= 3 + (6.4)(11)3014

= 3 + 4.416

= 3 + 0.275

= 3.275

= 3.3cm