A body is launched from the earth’s surface, of radius R, so that it just escapes from the gravitational influence of the earth; If the gravitational constant is G and the mass of the earth is M, what is the escape velocity of the boby.
\(\sqrt{2GM}\) รท R
\(\frac{\sqrt{2GM}}{R}\)
\(\frac{\sqrt{2G}}{MR}\)
\(\sqrt{2GMR}\)
\(\frac{\sqrt{R}}{2GM}\)
Correct answer is B
No explanation has been provided for this answer.