In a hydraulic press, a force of 40N is applied to the smaller piston of area 10cm2. If the area of the larger piston is 200cm2, calculate the force obtained

A.

800N

B.

500N

C.

80N

D.

50N

View answer & explanation

Correct answer is A

\(F_2 = \frac{F_1 \times A_2}{A_1} = \frac{40 \times 200}{10} = 800N\)

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