If the uncertainty in the measurement of the position of a particle is 5.0 x 10^-10m, the uncertainty in the momentum of the particle is

1.32 x 10^-44Ns

3.30 x 10^-44Ns

1.32 x 10^-24Ns

3.30 x 10^-24Ns

Correct answer is C

From the uncertainty principle the product of the position and momentum of a sub-atomic particle is equal or greater than planck's constant.

i.e $\Delta x. \Delta p \geq h. \\ \text{Thus} 5 \times 10^{-10} \times \Delta p = 6.6 \times 10^{-34} \\ \Delta p = \frac{6.6 \times 10^{-34}}{5 \times 10^{-10}} = 1.32 \times 10^{-24}Ns\\ \text{Therefore Uncertainty in the momentum } = 1.32 \times 10^{-24}Ns$

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