In an A.C circuit, the ratio of r.m.s value to peak value...
In an A.C circuit, the ratio of r.m.s value to peak value of current is
2
\( \frac{1}{2} \)
\( \frac{1}{\sqrt{2}} \)
\( \sqrt{2} \)
Correct answer is C
Irms = \( \frac{I_0}{\sqrt{2}} \)
\( \text{Therefore } \sqrt{2Irms} = I_0 \\
\frac{Irms}{I_0} = \frac{1}{\sqrt{2}} \)