A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms^-2]. Determine the potential energy of the body at the maximum height of its motion

0.36J

0.72J

360.00J

720.00J

Correct answer is A

P.E at max = K.E on projection

= \(\frac{1}{2}\)mv² = \(\frac{1}{2} \times 0.02 \times 6^2 = 0.36J\)

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A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms-2]. Determine the potential energy of the body at the maximum height of its motion