A stone, Q is thrown with velocity U at an angle of 75o to the horizontal. Another stone R is thrown with the same velocity U but with an angle of 15o to the horizontal. The ranges covered by the stones will be

A.

greater for Q

B.

greater for R

C.

the same for Q and R

D.

greater for the heavier of the two stones

Correct answer is C

Range = \(\frac{U^2sin2\theta}{g}\)

RangeQ = \(\frac{U^2sin150}{g}\)

RangeR = \(\frac{U^2sin30}{g}\)

Since, sin30o = sin150o

therefore, RQ = RR