A cylindrical motor of height 12cm has uniform thickness of 2cm. If the diameter of its outer cross section is 10cm, Find the volume of the constituent material. (take \(\pi\) = \(\frac{22}{7}\)

\(\frac{6600}{7}\)cm³

270cm³

660cm³

\(\frac{4224}{7}\)cm³

\(\frac{1980}{7}\)cm³

Correct answer is D

V = \(\pi\)r²h

= \(\frac{22}{7}\) x 5² x 12 - \(\frac{22}{7}\) x 3² x 12

= \(\frac{22}{7}\) x 12(5² - 3²)

= \(\frac{4224}{7}\)

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