A metal of mass 200g at a temperature of 100^oC is placed in 100g of water at 25^oC in a container of negligible heat capacity. If the final steady temperature is 30^oC, calculate the specific heat capacity of the metal. [specific heat capacity of the water is 4200 Jkg^-1 K^-1]

150 Jkg^-1K^-1

300 Jkg^-1K^-1

320 Jkg^-1K^-1

1960 Jkg^-1K^-1

Correct answer is A

MC\(\theta\)_metal = MC\(\theta _{water}\)

0.2 x C x 70 = 0.1 x 4200 x 5

C = 150

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A metal of mass 200g at a temperature of 100oC is placed in 100g of water at 25oC in a container of negligible heat capacity. If the final steady temperature is 30oC, calculate the specific heat capacity of the metal. [specific heat capacity of the water is 4200 Jkg-1 K-1]