5.0 x 10-2 ms-2
4.5 x 10--2 ms-3
2.5 x 10-2 ms-8
2.0 x 10-2 ms-3
Correct answer is C
With in the air = 250N
wt. in the liquid = 200N
loss in wt. in the liquid = 250 - 200 = 50N
∴ Wt. the liquid of equal vol. of the iron = 50N
∴If the density of the liquid is 1000 lgm-3
then the volume of the liquid = (N)/D = V = (25kg)/1000 =0.025m3 = 2.5 x 10-2 m8.
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