Determine the mean monthly salary of 50 employees of a company from the following frequency distribution.
\(\begin{array}{c|c} \text{Monthly salary} & \text{Frequency}\\\hline N200.00 & 10\\ N325.00 & 5\\N100.00 & 20\\N120.00 & 2\\ N60.00 & 10\\ N80.00 & 3\end{array}\)

A.

N215.30

B.

N134.10

C.

N143.10

D.

N80.00

E.

N50.30

Correct answer is B

\(\bar{x}\) = \(\frac{fx}{N}\)

= \(\frac{6705}{50}\)

= 1341

= N134.10