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Factorize completely 81a $^4$ - 16b $^4$ ...

Factorize completely 81a $^4$ - 16b $^4$

A.

(3a + 2b)(2a - 3b)(9a² + 4b²)

B.

(3a - 2b)(2a - 3b)(4a² - 9b²)

C.

(3a - 2b)(3a + 2b)(9a² + 4b²)

D.

(6a - 2b)(8a - 3b)(4a³ - 9b²)

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Correct answer is C

81a $^4$ - 16b $^4$ = (9a $^2$ ) $^2$ - (4b $^2$ ) $^2$

= (9a $^2$ + 4b $^2$ )(9a $^2$ - 4b $^2$ )

N:B 9a $^2$ - 4b $^2$ = (3a - 2b)(3a + 2b)

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