If pq + 1 = q² and t = $\frac{1}{p}$ - $\frac{1}{pq}$ express t in terms of q

$\frac{1}{p - q}$

$\frac{1}{q - 1}$

$\frac{1}{q + 1}$

1 + 0

$\frac{1}{1 - q}$

Correct answer is C

Pq + 1 = q²......(i)

t = $\frac{1}{p}$ - $\frac{1}{pq}$ .........(ii)

p = $\frac{q^2 - 1}{q}$

Sub for p in equation (ii)

t = $\frac{1}{q^2 - \frac{1}{q}}$ - $\frac{1}{\frac{q^2 - 1}{q} \times q}$

t = $\frac{q}{q^2 - 1}$ - $\frac{1}{q^2 - 1}$

t = $\frac{q - 1}{q^2 - 1}$

= $\frac{q - 1}{(q + 1)(q - 1)}$

= $\frac{1}{q + 1}$

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