1p−q
1q−1
1q+1
1 + 0
11−q
Correct answer is C
Pq + 1 = q2......(i)
t = 1p - 1pq.........(ii)
p = q2−1q
Sub for p in equation (ii)
t = 1q2−1q - 1q2−1q×q
t = qq2−1 - 1q2−1
t = q−1q2−1
= q−1(q+1)(q−1)
= 1q+1
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