7.0
6.0
5.2
5.0
Correct answer is B
Area of trapezium = 14cm2
Area of trapezium = \(\frac{1}{2}\)(a + b)h
14 = \(\frac{1}{2}\)(4 + 3)h
14 = \(\frac{7}{2}\)h
h = \(\frac{14 \times 2}{7}\)
= 4
Area of SQR = \(\frac{1}{2}\)(3 x 4)
= \(\frac{12}{2}\)
= 6.0