A bag contains 3 red, 4 black and 5 green identical balls. Two balls are picked at random, one after the other without replacement. Find the probability that one is red and the other is green
2/3
5/11
5/22
5/24
5/48
Correct answer is C
Total balls = 12
RG or GR
3/12
x
5/11
+
5/12
x
3/11
5/44
+
5/44
=
10/44
=
5/22