If three numbers P, Q, R are in ratio 6 : 4 : 5, find the value of \(\frac{3p - q}{4q + r}\)

A.

\(\frac{3}{2}\)

B.

\(\frac{2}{3}\)

C.

2

D.

3

Correct answer is B

P : Q : r = 6 : 4 : 5

5 = 6 + 4 + 5

= 15

P = \(\frac{6}{15}\), q = \(\frac{4}{15}\), r = \(\frac{5}{15}\) = \(\frac{1}{3}\)

To find \(\frac{3p - q}{4q + r}\)

3p - q = 3 x \(\frac{6}{15}\) - \(\frac{4}{15}\)

\(\frac{18}{15}\) - \(\frac{4}{15}\) = \(\frac{14}{15}\)

∴ 4q + r = 4 x \(\frac{4}{15}\) + \(\frac{5}{15}\)

\(\frac{16}{15}\) = \(\frac{16}{15}\) + \(\frac{5}{15}\)

= \(\frac{21}{15}\)

\(\frac{14}{15}\) x \(\frac{15}{21}\) = \(\frac{14}{21}\)

= \(\frac{2}{3}\)