A block of volume 3 x 10⁵m³ and density 2.5 x 10³ kg m^-3 is suspended from a spring balance with \(\frac{2}{3}\) of its volume immersed in a liquid of density 900 kg m^-3. Determine the reading of the spring balance [g = 10ms^-2]

0.18N

0.57N

0.75n

0.93N

Correct answer is B

Volume immersed solid = 3 x 10⁵ x \(\frac{2}{3}\)

= 2 x 10⁵m³

Mass of liquid displaced = ev

= 2 x 10⁵ x 900 = 18 x 10⁷ kg

Upthrust = 18 x 10⁷ x 10

= 7.8 x 10⁹N

Mass of solid = ev

= 2.5 x 10³ x 10⁵

= 7.5 x 10⁸

Weight of solid = 7.5 x 10⁸ x10 = 7.8 x 10⁹

Reading = 0.75 - 0.18 = 0.57N

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A block of volume 3 x 10⁵m³ and density 2.5 x 10³ kg m^-3 is suspended from a spring balance with \(\frac{2}{3}\) of its volume immersed in a liquid of density 900 kg m^-3. Determine the reading of the spring balance [g = 10ms^-2]

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A block of volume 3 x 10⁵m³ and density 2.5 x 10³ kg m^-3 is suspended from a spring balance with \(\frac{2}{3}\) of its volume immersed in a liquid of density 900 kg m^-3. Determine the reading of the spring balance [g = 10ms^-2]