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Make R the subject of the fomula S = \(\sqrt{\frac{2R + T}{2...

Make R the subject of the fomula S = $\sqrt{\frac{2R + T}{2RT}}$

A.

R = $\frac{T}{(TS^2 + 1)}$

B.

R = $\frac{T}{2(TS^2 - 2)}$

C.

R = $\frac{T}{2(TS^2 + 1)}$

D.

R = $\frac{R}{2(TS^2 + 1)}$

View answer & explanation

Correct answer is B

S = $\sqrt{\frac{2R + T}{2RT}}$

Squaring both sides,

$S^{2} = \frac{2R + T}{2RT}$

$S^{2} (2RT) = 2R + T$

$2S^{2} RT - 2R = T$

$R = \frac{T}{2TS^{2} - 2}$

= \(\frac{T}{2(TS^{2} - 1)}

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