What is the effective capacitance in the circuit?
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What is the effective capacitance in the circuit?
2\(\mu F\)
6\(\mu F\)
18\(\mu F\)
216\(\mu F\)
Correct answer is A
\(\frac{1}{c} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6}\)
= \(\frac{1 + 1 + 1}{6} = \frac{3}{6} = \frac{1}{2}\)
= 2\(\mu F\)
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