250g of lead at 170^oC is dropped into 100g of water at 0^oC. If the final temperature is 12^oC, the specific heat of lead is (specific heat of water is 4,200J/kg^oC)

39.5J/kg^oC

50.4J/kg^oC

127.6J/kg^oC

154.6J/kg^oC

173.4J/kg^oC

Correct answer is C

Heat lost = heat gained

0.25 x C₁ x (170 - 12) = 0.1 x 4200 x (12 - 0)

C₁ = 127.6J/kg^oC

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250g of lead at 170oC is dropped into 100g of water at 0oC. If the final temperature is 12oC, the specific heat of lead is (specific heat of water is 4,200J/kgoC)