1p−q
−1p+q
1pq
1pq(p−q)
Correct answer is B
1p - 1q ÷ pq - qp = q−ppq ÷ p2−q2pq
q−ppq x pqp2q2 = q−pp2−q2
−(p−q)(p+q)(p−q)
= −1p+q
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