A fixed mass of gas of volume 600cm3 at a temperature of 27oC is cooled at constant pressure to a temperature of 0oC. What is the change in volume?

A.

54cm2

B.

273cm2

C.

300cm2

D.

546cm2

E.

600cm2

View answer & explanation

Correct answer is A

\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

T2 = 0 + 273 = 273k

V1 = 600

T1 = 27 + 273 = 300k

V2 = \(\frac{V_1T_2}{T_1}\) = 546cm

V1 - V2 = 54cm

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