A heater marked 50W will evaporate 0.005kg of boiling water in 50 seconds. The specific latent heat of vaporization of water in J/kg is

A.

5.0 x 10⁶

B.

1.0 x 10⁶

C.

2.5 x 10⁶

D.

2.5 x 10⁵

E.

5.0 x 10⁵

View answer & explanation

Correct answer is E

Heat energy = Electrical energy

mL = power x time

0.005 x L = 50 x 50

L = 5 x 10⁵J/kg

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