5√3
6√3
8√3
18√3
Correct answer is B
\(\sqrt{48}\) - \(\frac{9}{\sqrt{3}}\) + \(\sqrt{75}\)
Rearrange = \(\sqrt{48}\) + \(\sqrt{75}\) - \(\frac{9}{\sqrt{3}}\)
= (√16 x √3) + (√25 x √3) - \(\frac{9}{\sqrt{3}}\)
=4√3 + 5√3 - \(\frac{9}{\sqrt{3}}\)
Rationalize \(\to\) 9√3 = \(\frac{9}{\sqrt{3}}\) x \(\frac{\sqrt{3}}{\sqrt{3}}\)
= \(\frac{9\sqrt{3}}{\sqrt{9}}\) - \(\frac{9\sqrt{3}}{\sqrt{3}}\)
= 3√3
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