5
√6
53
√5
Correct answer is D
class intervalsFre(F)class-marks(x)Fx(x−x)(x−x)2F(x−x)21−35210−39454−685400007−958403945189090
x = ∑fx∑f
= 9018
= 5
S.D = ∑f(x−x)2∑f
= 9018
= √5
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