\(\begin{vmatrix} -2 & 1 & 1 \\ 2 & 1 & k \\1 & 3 & -1 \end{vmatrix}\) = 23

A.

1

B.

2

C.

3

D.

4

View answer & explanation

Correct answer is B

-2(-1 - 3k) - 1(-2 -k) + 1(6 - 1) = 23

7k = 14

k = 2

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