A temperature 20°C is the same as
36oF
68oF
11.1oF
43.1oF
25oF
Correct answer is B
212°F ... 100°C θ°F ... 20°C 32°F ... 0°C θ−32212−32 = 20−0100−0
180 = 5(θ - 32)
5θ = 180 + 160 = 340
θ = 68°F
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