Given that log_a2 = 0.693 and log_a3 = 1.097, find log_a 13.5

A.

1.404

B.

1.790

C.

2.598

D.

2.790

View answer & explanation

Correct answer is C

log_a 13.5 = log_a \(\frac{27}{2}\)

= 3log_a 3 - log²_a

= 3 x 1.097 - 0.693

= 2.598

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