The hatch door of a submarine has an area of 0.5m2. The specific gravity of sea water is 1.03. Assume that g = 10ms-1,and neglect the atmospheric pressure. The force exerted by the sea water on the hatch door at a depth of 200m is

A.

1.03 x 105N

B.

1.03 x 104Nm-2

C.

1.06 x 105Nm-2

D.

2.06 x 106N

E.

1.03 x 103N

Correct answer is E

Pressure in liquid = e x h x g

Pressure in solid = \(\frac{force}{area}\)

\(\frac{force}{area}\) = e x h x g

force = 0.5 x 10 x 200 x 1.03

= 1030N