A 90W immersion heater is used to supply energy for 5 minutes. The energy supplied is used to completely melt 160g of a solid at its melting point. Calculate the specific latent heat of the solid.
2.81jg-1
6.25Jg-1
8.89Jg-1
168.75Jg-1
5333.33Jg-1
Correct answer is D
pt = ml 80
90 x 5 x 60 = 160 x L
L = \(\frac{27000}{160}\)
= 168.75Jg-1
= 168.75