Hot water is added to three times its mass of water at 10^oC and the resultant temperature is 20^oC. What is the initial temperature of the hot water?

100^oC

80^oC

50^oC

40^oC

Correct answer is C

Heat loss = heat gained

m_h x c_h x \(\theta\)_h = m_c x c_c x \(\theta\)_c

m_h x c_h x (\(\theta\) - 20) = m_c x c_c x (20 - 10)

c_h = c_c ; m_c = 3m_h

therefore, \(\theta\) = 50^oC

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Hot water is added to three times its mass of water at 10oC and the resultant temperature is 20oC. What is the initial temperature of the hot water?

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Hot water is added to three times its mass of water at 10^oC and the resultant temperature is 20^oC. What is the initial temperature of the hot water?