100oC
80oC
50oC
40oC
Correct answer is C
Heat loss = heat gained mh x ch x \(\theta\)h = mc x cc x \(\theta\)c mh x ch x (\(\theta\) - 20) = mc x cc x (20 - 10) ch = cc ; mc = 3mh therefore, \(\theta\) = 50oC
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