In a ∆ XYZ, /YZ/ = 6cm YXZ = 60^o and XYZ is a right angle. Calculate /XZ/in cm, leaving your answer in surd form

2√3

4√3

6√3

12√3

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Correct answer is B

$sin \theta = \frac{opp}{hyp}\\ sin 60^o = \frac{|YZ|}{|XZ|}=\frac{6}{P}\\ P sin 60^o = 6\\ P = \frac{6}{sin60^o}\\ =\frac{6}{\sqrt{\frac{3}{2}}}=4\sqrt{3}$

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In a ∆ XYZ, /YZ/ = 6cm YXZ = 60o and XYZ is a right angle. Calculate /XZ/in cm, leaving your answer in surd form

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In a ∆ XYZ, /YZ/ = 6cm YXZ = 60^o and XYZ is a right angle. Calculate /XZ/in cm, leaving your answer in surd form