The equation of the line through the points (4,2) and (-8...
The equation of the line through the points (4,2) and (-8, -2) is 3y = px + q, where p and q are constants. Find the value of p.
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Correct answer is A
Using the two - point from
y−y1y2−y1=x−x1x2−x1
y−2−2−2=x−4−8−4
y−2−4=x−4−12
−12(y−2)−4 = x - 4
3(y -2) = x -4
3y - 6 = x - 4
3y = x - 4 + 6
3y = x + 2...
By comparing the equations;
3y = px + , p = 1
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