$^{27}_{13}Al$ + $^{1}_{0}n$ $\Rightarrow$ $^{24}_{11}Na$ + X

a proton

a gamma ray

a helium particle

an alpha particle

View answer & explanation

Correct answer is D

$^{27}_{13}Al$ + $^{1}_{0}n$ $\Rightarrow$ $^{24}_{11}Na$ + $^{b}_{a}X$

a + 11 = 0 + 13 $\Rightarrow$ a = 2

b + 24 = 1 + 27 $\Rightarrow$ b = 4

$^{b}_{a}X$ = $^{4}_{2}\alpha$

See all Physics questions & answers

See more JAMB questions & answers

Aptitude Tests

Typing Speed and Accuracy Test

Numerical Reasoning Questions and Answers

Spatial Reasoning Questions and Answers

Microsoft Office Questions and Answers

Situational Judgement Questions and Answers

Verbal Reasoning Questions and Answers

Abstract Reasoning Questions and Answers

Puzzles Questions and Answers

Personality Test

Nigeria General Knowledge Questions and Answers

Data Interpretation Questions and Answers

Logical Reasoning Questions and Answers

Quantitative Reasoning Questions and Answers

See all →

View latest jobs in Nigeria today

2713Al^{27}_{13}Al + 10n^{1}_{0}n ⇒\Rightarrow 2411Na^{24}_{11}Na + X

Similar Questions

Aptitude Tests

$^{27}_{13}Al$ + $^{1}_{0}n$ $\Rightarrow$ $^{24}_{11}Na$ + X