The density of 400cm³ of palm oil was 0.9gcm^-3 before frying. If the density of the oil was 0.6gm^-3 after frying,assuming no loss of oil due to spilling, its new volume was

360cm³

600cm³

240cm³

800cm³

450cm³

Correct answer is B

Since no loss of oil,

Density x volume = constant

D₁V₁ = D₂ x V₂

0.9 x 400 = V₂

V₂ = 600cm³

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The density of 400cm3 of palm oil was 0.9gcm-3 before frying. If the density of the oil was 0.6gm-3 after frying,assuming no loss of oil due to spilling, its new volume was