The ages of three men are in the ratio 3:4:5. If the diff...
The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men
45 years
72 years
108 years
216 years
Correct answer is C
Given that the ages are in the ratio 3: 4: 5.
Let the sum of their ages be t.
\(\therefore\) The youngest age = \(\frac{3}{12} t\)
The eldest age = \(\frac{5}{12} t\)
\(\implies \frac{5}{12} t - \frac{3}{12} t = 18\)
\(\frac{2t}{12} = 18 \implies t = \frac{18 \times 12}{2}\)
t = 108 years.
The sum of their ages = 108 years.
From the diagram, find the value of x in the diagram....
In the diagram above, O is the centre of the circle through points L, M and N, if ∠MLN = 74o and...
The graph of f(x) = x2 - 5x + 6 crosses the x-axis at the points...
The following is the graph of a quadratic friction, find the value of x when y = 0 ...
If sin θ = -1/2 for 0 < θ < 360o, the value of θ is ...
If N varies directly as M and N = 8 when M = 20 find M when N = 7 ...
IF the exterior angles of a quadilateral are yo, (2y + 5)o , (y + 15)o and (3y - 10)o, find yo...
A side and a diagonal of a rhombus are 10cm and 12cm respectively, Find its area ...