Two 50\(\mu\)F parallel plate capacitors are connected in series. The combined capacitor is then connected across a 100-V battery. The charge on each plate of the capacitor is

A.

5.00 x 10-5C

B.

2.50 x 10-3C

C.

1.25 x 10-3C

D.

1.00 x 10-2C

View answer & explanation

Correct answer is D

For series, C = \(\frac{50 \times\ 50}{50 + 50}\)

C= 25\(\mu\)F

Q = CV

Q = 25 x 100 x 10-3

Q = 2.5 x 10-3C

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